Base | Representation |
---|---|
bin | 1011011110011010001010… |
… | …0001110111010100000101 |
3 | 1122200011210121111012100122 |
4 | 2313212202201313110011 |
5 | 3123204202202002121 |
6 | 42500105113351325 |
7 | 2441360104142654 |
oct | 267464241672405 |
9 | 48604717435318 |
10 | 12617045734661 |
11 | 402494a434115 |
12 | 14b9327108545 |
13 | 706a22964304 |
14 | 31894da4919b |
15 | 16d2e949b5ab |
hex | b79a2877505 |
12617045734661 has 8 divisors (see below), whose sum is σ = 12709155264960. Its totient is φ = 12524955339168.
The previous prime is 12617045734649. The next prime is 12617045734687. The reversal of 12617045734661 is 16643754071621.
12617045734661 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12617045734661 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12617045734691) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3458801 + ... + 6098966.
It is an arithmetic number, because the mean of its divisors is an integer number (1588644408120).
Almost surely, 212617045734661 is an apocalyptic number.
It is an amenable number.
12617045734661 is a deficient number, since it is larger than the sum of its proper divisors (92109530299).
12617045734661 is an equidigital number, since it uses as much as digits as its factorization.
12617045734661 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9567403.
The product of its (nonzero) digits is 5080320, while the sum is 53.
The spelling of 12617045734661 in words is "twelve trillion, six hundred seventeen billion, forty-five million, seven hundred thirty-four thousand, six hundred sixty-one".
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