Base | Representation |
---|---|
bin | 1011011110011010101111… |
… | …0101010111011010010001 |
3 | 1122200012012111020021002212 |
4 | 2313212223311113122101 |
5 | 3123210012132414214 |
6 | 42500132411321505 |
7 | 2441364011056565 |
oct | 267465365273221 |
9 | 48605174207085 |
10 | 12617201841809 |
11 | 4024a1a567794 |
12 | 14b936b450295 |
13 | 706a490c0bc6 |
14 | 3189666836a5 |
15 | 16d30803553e |
hex | b79abd57691 |
12617201841809 has 2 divisors, whose sum is σ = 12617201841810. Its totient is φ = 12617201841808.
The previous prime is 12617201841773. The next prime is 12617201841823. The reversal of 12617201841809 is 90814810271621.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6572414123584 + 6044787718225 = 2563672^2 + 2458615^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12617201841809 is a prime.
It is not a weakly prime, because it can be changed into another prime (12617201841859) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6308600920904 + 6308600920905.
It is an arithmetic number, because the mean of its divisors is an integer number (6308600920905).
Almost surely, 212617201841809 is an apocalyptic number.
It is an amenable number.
12617201841809 is a deficient number, since it is larger than the sum of its proper divisors (1).
12617201841809 is an equidigital number, since it uses as much as digits as its factorization.
12617201841809 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 387072, while the sum is 50.
The spelling of 12617201841809 in words is "twelve trillion, six hundred seventeen billion, two hundred one million, eight hundred forty-one thousand, eight hundred nine".
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