Base | Representation |
---|---|
bin | 10010010111111010101… |
… | …011000001100000100111 |
3 | 11110201001220222120100221 |
4 | 102113322223001200213 |
5 | 131141332014000403 |
6 | 2404013352145211 |
7 | 160136113263664 |
oct | 22277253014047 |
9 | 4421056876327 |
10 | 1262631000103 |
11 | 44752a312500 |
12 | 184858698207 |
13 | 920b1150095 |
14 | 4517c5aca6b |
15 | 22c9d3e3dbd |
hex | 125faac1827 |
1262631000103 has 6 divisors (see below), whose sum is σ = 1387850603552. Its totient is φ = 1147846363620.
The previous prime is 1262631000083. The next prime is 1262631000121. The reversal of 1262631000103 is 3010001362621.
It is not a de Polignac number, because 1262631000103 - 213 = 1262630991911 is a prime.
It is a super-3 number, since 3×12626310001033 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1262631001103) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 5217483351 + ... + 5217483592.
Almost surely, 21262631000103 is an apocalyptic number.
1262631000103 is a deficient number, since it is larger than the sum of its proper divisors (125219603449).
1262631000103 is a wasteful number, since it uses less digits than its factorization.
1262631000103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10434966965 (or 10434966954 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 1262631000103 its reverse (3010001362621), we get a palindrome (4272632362724).
The spelling of 1262631000103 in words is "one trillion, two hundred sixty-two billion, six hundred thirty-one million, one hundred three", and thus it is an aban number.
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