Base | Representation |
---|---|
bin | 1011011111010010000100… |
… | …0111011011100101001101 |
3 | 1122201121112120222002101001 |
4 | 2313310201013123211031 |
5 | 3123430421412214040 |
6 | 42511030301420301 |
7 | 2442431040620362 |
oct | 267644107334515 |
9 | 48647476862331 |
10 | 12632054413645 |
11 | 4030251443847 |
12 | 150021556a691 |
13 | 70827522b854 |
14 | 31957508c469 |
15 | 16d8c6e2759a |
hex | b7d211db94d |
12632054413645 has 16 divisors (see below), whose sum is σ = 15831792040320. Its totient is φ = 9657551425984.
The previous prime is 12632054413621. The next prime is 12632054413681. The reversal of 12632054413645 is 54631445023621.
It is a cyclic number.
It is not a de Polignac number, because 12632054413645 - 211 = 12632054411597 is a prime.
It is a super-5 number, since 5×126320544136455 (a number of 67 digits) contains 55555 as substring. Note that it is a super-d number also for d = 3.
It is a junction number, because it is equal to n+sod(n) for n = 12632054413595 and 12632054413604.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 49396339 + ... + 49651408.
It is an arithmetic number, because the mean of its divisors is an integer number (989487002520).
Almost surely, 212632054413645 is an apocalyptic number.
It is an amenable number.
12632054413645 is a deficient number, since it is larger than the sum of its proper divisors (3199737626675).
12632054413645 is a wasteful number, since it uses less digits than its factorization.
12632054413645 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 99048884.
The product of its (nonzero) digits is 2073600, while the sum is 46.
The spelling of 12632054413645 in words is "twelve trillion, six hundred thirty-two billion, fifty-four million, four hundred thirteen thousand, six hundred forty-five".
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