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12632054411597 is a prime number
BaseRepresentation
bin1011011111010010000100…
…0111011011000101001101
31122201121112120221222120012
42313310201013123011031
53123430421412132342
642511030301403005
72442431040611405
oct267644107330515
948647476858505
1012632054411597
114030251442255
121500215569465
1370827522a93a
1431957508b805
1516d8c6e26b82
hexb7d211db14d

12632054411597 has 2 divisors, whose sum is σ = 12632054411598. Its totient is φ = 12632054411596.

The previous prime is 12632054411527. The next prime is 12632054411659. The reversal of 12632054411597 is 79511445023621.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12318934707556 + 313119704041 = 3509834^2 + 559571^2 .

It is a cyclic number.

It is not a de Polignac number, because 12632054411597 - 212 = 12632054407501 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12632054411527) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6316027205798 + 6316027205799.

It is an arithmetic number, because the mean of its divisors is an integer number (6316027205799).

Almost surely, 212632054411597 is an apocalyptic number.

It is an amenable number.

12632054411597 is a deficient number, since it is larger than the sum of its proper divisors (1).

12632054411597 is an equidigital number, since it uses as much as digits as its factorization.

12632054411597 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1814400, while the sum is 50.

The spelling of 12632054411597 in words is "twelve trillion, six hundred thirty-two billion, fifty-four million, four hundred eleven thousand, five hundred ninety-seven".