Base | Representation |
---|---|
bin | 10111100001110111… |
… | …10000111100111001 |
3 | 1012121100120212101211 |
4 | 23300323300330321 |
5 | 201332311232213 |
6 | 5445250243121 |
7 | 625015235233 |
oct | 136073607471 |
9 | 35540525354 |
10 | 12632133433 |
11 | 53a25678a7 |
12 | 25465864a1 |
13 | 126410148a |
14 | 87b96b253 |
15 | 4dded953d |
hex | 2f0ef0f39 |
12632133433 has 2 divisors, whose sum is σ = 12632133434. Its totient is φ = 12632133432.
The previous prime is 12632133421. The next prime is 12632133443. The reversal of 12632133433 is 33433123621.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12412856569 + 219276864 = 111413^2 + 14808^2 .
It is a cyclic number.
It is not a de Polignac number, because 12632133433 - 25 = 12632133401 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12632133395 and 12632133404.
It is not a weakly prime, because it can be changed into another prime (12632133443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6316066716 + 6316066717.
It is an arithmetic number, because the mean of its divisors is an integer number (6316066717).
Almost surely, 212632133433 is an apocalyptic number.
It is an amenable number.
12632133433 is a deficient number, since it is larger than the sum of its proper divisors (1).
12632133433 is an equidigital number, since it uses as much as digits as its factorization.
12632133433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 23328, while the sum is 31.
The spelling of 12632133433 in words is "twelve billion, six hundred thirty-two million, one hundred thirty-three thousand, four hundred thirty-three".
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