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12634044403 is a prime number
BaseRepresentation
bin10111100010000110…
…00011011111110011
31012121111011221202111
423301003003133303
5201333303410103
65445355230151
7625040414461
oct136103033763
935544157674
1012634044403
1153a3652612
122547148357
131264620226
1487bd07831
154de26586d
hex2f10c37f3

12634044403 has 2 divisors, whose sum is σ = 12634044404. Its totient is φ = 12634044402.

The previous prime is 12634044361. The next prime is 12634044413. The reversal of 12634044403 is 30444043621.

It is a strong prime.

It is an emirp because it is prime and its reverse (30444043621) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12634044403 is a prime.

It is not a weakly prime, because it can be changed into another prime (12634044413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6317022201 + 6317022202.

It is an arithmetic number, because the mean of its divisors is an integer number (6317022202).

Almost surely, 212634044403 is an apocalyptic number.

12634044403 is a deficient number, since it is larger than the sum of its proper divisors (1).

12634044403 is an equidigital number, since it uses as much as digits as its factorization.

12634044403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27648, while the sum is 31.

The spelling of 12634044403 in words is "twelve billion, six hundred thirty-four million, forty-four thousand, four hundred three".