Base | Representation |
---|---|
bin | 1011011111110011110011… |
… | …1011110001111100000111 |
3 | 1122202110220202122012021101 |
4 | 2313330330323301330013 |
5 | 3124102443412244020 |
6 | 42515125105000531 |
7 | 2443201342043032 |
oct | 267747473617407 |
9 | 48673822565241 |
10 | 12641111056135 |
11 | 4034079702351 |
12 | 1501b22623147 |
13 | 7090896517c3 |
14 | 319b93c0a019 |
15 | 16dc5709200a |
hex | b7f3cef1f07 |
12641111056135 has 16 divisors (see below), whose sum is σ = 15678736690176. Its totient is φ = 9778471331488.
The previous prime is 12641111056087. The next prime is 12641111056151. The reversal of 12641111056135 is 53165011114621.
It is a cyclic number.
It is not a de Polignac number, because 12641111056135 - 223 = 12641102667527 is a prime.
It is a super-2 number, since 2×126411110561352 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12641111056094 and 12641111056103.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 324028459 + ... + 324067468.
It is an arithmetic number, because the mean of its divisors is an integer number (979921043136).
Almost surely, 212641111056135 is an apocalyptic number.
12641111056135 is a deficient number, since it is larger than the sum of its proper divisors (3037625634041).
12641111056135 is an equidigital number, since it uses as much as digits as its factorization.
12641111056135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 648096062.
The product of its (nonzero) digits is 21600, while the sum is 37.
The spelling of 12641111056135 in words is "twelve trillion, six hundred forty-one billion, one hundred eleven million, fifty-six thousand, one hundred thirty-five".
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