Base | Representation |
---|---|
bin | 1011011111110100111000… |
… | …1100000111001011110111 |
3 | 1122202111122221101000101101 |
4 | 2313331032030013023313 |
5 | 3124104042020101020 |
6 | 42515213525510531 |
7 | 2443211455514620 |
oct | 267751614071367 |
9 | 48674587330341 |
10 | 12641400550135 |
11 | 4034208060495 |
12 | 1501ba3572447 |
13 | 709104611626 |
14 | 319bc0446a47 |
15 | 16dc726c800a |
hex | b7f4e3072f7 |
12641400550135 has 32 divisors (see below), whose sum is σ = 17350886191104. Its totient is φ = 8661337776000.
The previous prime is 12641400550133. The next prime is 12641400550193. The reversal of 12641400550135 is 53105500414621.
It is not a de Polignac number, because 12641400550135 - 21 = 12641400550133 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12641400550094 and 12641400550103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12641400550133) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 222097330 + ... + 222154240.
It is an arithmetic number, because the mean of its divisors is an integer number (542215193472).
Almost surely, 212641400550135 is an apocalyptic number.
12641400550135 is a deficient number, since it is larger than the sum of its proper divisors (4709485640969).
12641400550135 is a wasteful number, since it uses less digits than its factorization.
12641400550135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61975.
The product of its (nonzero) digits is 72000, while the sum is 37.
Adding to 12641400550135 its reverse (53105500414621), we get a palindrome (65746900964756).
The spelling of 12641400550135 in words is "twelve trillion, six hundred forty-one billion, four hundred million, five hundred fifty thousand, one hundred thirty-five".
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