Base | Representation |
---|---|
bin | 1011011111111100011010… |
… | …1001111100110111110111 |
3 | 1122202200212210101220220111 |
4 | 2313333012221330313313 |
5 | 3124122211414410020 |
6 | 42520150244443451 |
7 | 2443312526466511 |
oct | 267770651746767 |
9 | 48680783356814 |
10 | 12643421638135 |
11 | 40350549a0852 |
12 | 15024683a9587 |
13 | 7093672603a2 |
14 | 319d32a30bb1 |
15 | 16dd3ed53d5a |
hex | b7fc6a7cdf7 |
12643421638135 has 16 divisors (see below), whose sum is σ = 15208517217600. Its totient is φ = 10090492240896.
The previous prime is 12643421638103. The next prime is 12643421638139. The reversal of 12643421638135 is 53183612434621.
It is a cyclic number.
It is not a de Polignac number, because 12643421638135 - 25 = 12643421638103 is a prime.
It is a super-2 number, since 2×126434216381352 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12643421638139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1659847 + ... + 5295463.
It is an arithmetic number, because the mean of its divisors is an integer number (950532326100).
Almost surely, 212643421638135 is an apocalyptic number.
12643421638135 is a deficient number, since it is larger than the sum of its proper divisors (2565095579465).
12643421638135 is an equidigital number, since it uses as much as digits as its factorization.
12643421638135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3637290.
The product of its digits is 2488320, while the sum is 49.
The spelling of 12643421638135 in words is "twelve trillion, six hundred forty-three billion, four hundred twenty-one million, six hundred thirty-eight thousand, one hundred thirty-five".
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