Base | Representation |
---|---|
bin | 111010111000001000… |
… | …0100011000000101001 |
3 | 110002100122100022120212 |
4 | 1311300100203000221 |
5 | 4032420440444411 |
6 | 134030133030505 |
7 | 12064144325465 |
oct | 1656020430051 |
9 | 402318308525 |
10 | 126437437481 |
11 | 49692701193 |
12 | 20607785435 |
13 | bbccaa1a84 |
14 | 61962a34a5 |
15 | 34501e968b |
hex | 1d70423029 |
126437437481 has 2 divisors, whose sum is σ = 126437437482. Its totient is φ = 126437437480.
The previous prime is 126437437453. The next prime is 126437437507. The reversal of 126437437481 is 184734734621.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 100615840000 + 25821597481 = 317200^2 + 160691^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-126437437481 is a prime.
It is a super-2 number, since 2×1264374374812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (126437437681) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63218718740 + 63218718741.
It is an arithmetic number, because the mean of its divisors is an integer number (63218718741).
Almost surely, 2126437437481 is an apocalyptic number.
It is an amenable number.
126437437481 is a deficient number, since it is larger than the sum of its proper divisors (1).
126437437481 is an equidigital number, since it uses as much as digits as its factorization.
126437437481 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2709504, while the sum is 50.
The spelling of 126437437481 in words is "one hundred twenty-six billion, four hundred thirty-seven million, four hundred thirty-seven thousand, four hundred eighty-one".
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