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126455906347 is a prime number
BaseRepresentation
bin111010111000101011…
…1000000000000101011
3110002101221002122002221
41311301113000000223
54032440203000342
6134032032534511
712064460316541
oct1656127000053
9402357078087
10126455906347
11496a2076111
12206119b1437
13bc0386a2b4
14619890dd91
153451b46a67
hex1d715c002b

126455906347 has 2 divisors, whose sum is σ = 126455906348. Its totient is φ = 126455906346.

The previous prime is 126455906299. The next prime is 126455906389. The reversal of 126455906347 is 743609554621.

It is a strong prime.

It is an emirp because it is prime and its reverse (743609554621) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 126455906347 - 219 = 126455382059 is a prime.

It is a super-3 number, since 3×1264559063473 (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 126455906294 and 126455906303.

It is not a weakly prime, because it can be changed into another prime (126455906047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63227953173 + 63227953174.

It is an arithmetic number, because the mean of its divisors is an integer number (63227953174).

Almost surely, 2126455906347 is an apocalyptic number.

126455906347 is a deficient number, since it is larger than the sum of its proper divisors (1).

126455906347 is an equidigital number, since it uses as much as digits as its factorization.

126455906347 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5443200, while the sum is 52.

The spelling of 126455906347 in words is "one hundred twenty-six billion, four hundred fifty-five million, nine hundred six thousand, three hundred forty-seven".