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12654267145153 is a prime number
BaseRepresentation
bin1011100000100100110100…
…0110010001101111000001
31122210201212122010202121121
42320021031012101233001
53124311414342121103
642525142353352241
72444145352000504
oct270111506215701
948721778122547
1012654267145153
11403970a9a8797
121504594568681
1370a3a5174a6a
1431a6811a713b
1516e2770776bd
hexb824d191bc1

12654267145153 has 2 divisors, whose sum is σ = 12654267145154. Its totient is φ = 12654267145152.

The previous prime is 12654267145141. The next prime is 12654267145199. The reversal of 12654267145153 is 35154176245621.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9755583832449 + 2898683312704 = 3123393^2 + 1702552^2 .

It is a cyclic number.

It is not a de Polignac number, because 12654267145153 - 213 = 12654267136961 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12654267145153.

It is not a weakly prime, because it can be changed into another prime (12654267148153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6327133572576 + 6327133572577.

It is an arithmetic number, because the mean of its divisors is an integer number (6327133572577).

Almost surely, 212654267145153 is an apocalyptic number.

It is an amenable number.

12654267145153 is a deficient number, since it is larger than the sum of its proper divisors (1).

12654267145153 is an equidigital number, since it uses as much as digits as its factorization.

12654267145153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6048000, while the sum is 52.

The spelling of 12654267145153 in words is "twelve trillion, six hundred fifty-four billion, two hundred sixty-seven million, one hundred forty-five thousand, one hundred fifty-three".