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12660123515513 is a prime number
BaseRepresentation
bin1011100000111010101000…
…1010100011101001111001
31122211021222202221012110112
42320032222022203221321
53124410413104444023
642531551435554105
72444443443220535
oct270165212435171
948737882835415
1012660123515513
1140411457484a1
1215057498bb935
1370aac9562376
1431aa78ca8bc5
1516e4bb28d478
hexb83aa2a3a79

12660123515513 has 2 divisors, whose sum is σ = 12660123515514. Its totient is φ = 12660123515512.

The previous prime is 12660123515461. The next prime is 12660123515521. The reversal of 12660123515513 is 31551532106621.

12660123515513 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10491328297024 + 2168795218489 = 3239032^2 + 1472683^2 .

It is a cyclic number.

It is not a de Polignac number, because 12660123515513 - 212 = 12660123511417 is a prime.

It is not a weakly prime, because it can be changed into another prime (12660123515563) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6330061757756 + 6330061757757.

It is an arithmetic number, because the mean of its divisors is an integer number (6330061757757).

Almost surely, 212660123515513 is an apocalyptic number.

It is an amenable number.

12660123515513 is a deficient number, since it is larger than the sum of its proper divisors (1).

12660123515513 is an equidigital number, since it uses as much as digits as its factorization.

12660123515513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162000, while the sum is 41.

The spelling of 12660123515513 in words is "twelve trillion, six hundred sixty billion, one hundred twenty-three million, five hundred fifteen thousand, five hundred thirteen".