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12660932254081 is a prime number
BaseRepresentation
bin1011100000111101101001…
…0111101001100110000001
31122211101002010201101012211
42320033122113221212001
53124414042124112311
642532204010022121
72444502463331116
oct270173227514601
948741063641184
1012660932254081
114041520207781
121505934717941
1370abc7c848b7
1431ab1446a90d
1516e51728e821
hexb83da5e9981

12660932254081 has 2 divisors, whose sum is σ = 12660932254082. Its totient is φ = 12660932254080.

The previous prime is 12660932254051. The next prime is 12660932254247. The reversal of 12660932254081 is 18045223906621.

12660932254081 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10236032384400 + 2424899869681 = 3199380^2 + 1557209^2 .

It is a cyclic number.

It is not a de Polignac number, because 12660932254081 - 215 = 12660932221313 is a prime.

It is a super-2 number, since 2×126609322540812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12660932254051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6330466127040 + 6330466127041.

It is an arithmetic number, because the mean of its divisors is an integer number (6330466127041).

Almost surely, 212660932254081 is an apocalyptic number.

It is an amenable number.

12660932254081 is a deficient number, since it is larger than the sum of its proper divisors (1).

12660932254081 is an equidigital number, since it uses as much as digits as its factorization.

12660932254081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1244160, while the sum is 49.

The spelling of 12660932254081 in words is "twelve trillion, six hundred sixty billion, nine hundred thirty-two million, two hundred fifty-four thousand, eighty-one".