Base | Representation |
---|---|
bin | 10111101000101001… |
… | …11011011111111011 |
3 | 1012202022201010112221 |
4 | 23310110323133323 |
5 | 201441344440013 |
6 | 5455042344511 |
7 | 626306150341 |
oct | 136424733773 |
9 | 35668633487 |
10 | 12689061883 |
11 | 5421710003 |
12 | 256165b137 |
13 | 1272b44354 |
14 | 885349991 |
15 | 4e3ed208d |
hex | 2f453b7fb |
12689061883 has 2 divisors, whose sum is σ = 12689061884. Its totient is φ = 12689061882.
The previous prime is 12689061839. The next prime is 12689061893. The reversal of 12689061883 is 38816098621.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12689061883 - 217 = 12688930811 is a prime.
It is a super-3 number, since 3×126890618833 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 12689061883.
It is not a weakly prime, because it can be changed into another prime (12689061893) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6344530941 + 6344530942.
It is an arithmetic number, because the mean of its divisors is an integer number (6344530942).
Almost surely, 212689061883 is an apocalyptic number.
12689061883 is a deficient number, since it is larger than the sum of its proper divisors (1).
12689061883 is an equidigital number, since it uses as much as digits as its factorization.
12689061883 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 995328, while the sum is 52.
The spelling of 12689061883 in words is "twelve billion, six hundred eighty-nine million, sixty-one thousand, eight hundred eighty-three".
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