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12704113 is a prime number
BaseRepresentation
bin110000011101…
…100101110001
3212220102202201
4300131211301
511223012423
61132143201
7212661142
oct60354561
925812681
1012704113
117197874
124307b01
13282a636
141989ac9
1511ae2ad
hexc1d971

12704113 has 2 divisors, whose sum is σ = 12704114. Its totient is φ = 12704112.

The previous prime is 12704093. The next prime is 12704129. The reversal of 12704113 is 31140721.

12704113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11888704 + 815409 = 3448^2 + 903^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12704113 is a prime.

It is a super-2 number, since 2×127041132 = 322788974233538, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12704213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6352056 + 6352057.

It is an arithmetic number, because the mean of its divisors is an integer number (6352057).

Almost surely, 212704113 is an apocalyptic number.

It is an amenable number.

12704113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12704113 is an equidigital number, since it uses as much as digits as its factorization.

12704113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168, while the sum is 19.

The square root of 12704113 is about 3564.2829573422. The cubic root of 12704113 is about 233.3358392021.

Adding to 12704113 its reverse (31140721), we get a palindrome (43844834).

The spelling of 12704113 in words is "twelve million, seven hundred four thousand, one hundred thirteen".