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12710560331473 is a prime number
BaseRepresentation
bin1011100011110110100001…
…1011101111011011010001
31200000010011210200220221021
42320331220123233123101
53131222211421101343
643011052323555441
72451210351122314
oct270755033573321
950003153626837
1012710560331473
114060577a41874
121513484b2bb81
137127a6963b74
1431d2a162497b
1517096e16a0ed
hexb8f686ef6d1

12710560331473 has 2 divisors, whose sum is σ = 12710560331474. Its totient is φ = 12710560331472.

The previous prime is 12710560331377. The next prime is 12710560331501. The reversal of 12710560331473 is 37413306501721.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10259932890769 + 2450627440704 = 3203113^2 + 1565448^2 .

It is an emirp because it is prime and its reverse (37413306501721) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12710560331473 is a prime.

It is not a weakly prime, because it can be changed into another prime (12710560311473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6355280165736 + 6355280165737.

It is an arithmetic number, because the mean of its divisors is an integer number (6355280165737).

Almost surely, 212710560331473 is an apocalyptic number.

It is an amenable number.

12710560331473 is a deficient number, since it is larger than the sum of its proper divisors (1).

12710560331473 is an equidigital number, since it uses as much as digits as its factorization.

12710560331473 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 317520, while the sum is 43.

The spelling of 12710560331473 in words is "twelve trillion, seven hundred ten billion, five hundred sixty million, three hundred thirty-one thousand, four hundred seventy-three".