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1271065125793 is a prime number
BaseRepresentation
bin10010011111110001011…
…000101010001110100001
311111111211201021112202111
4102133301120222032201
5131311120133011133
62411530320515321
7160555115206501
oct22376130521641
94444751245674
101271065125793
11450068143a11
1218641117bb41
1392b265c25b8
144573c7a1a01
15230e3a941cd
hex127f162a3a1

1271065125793 has 2 divisors, whose sum is σ = 1271065125794. Its totient is φ = 1271065125792.

The previous prime is 1271065125763. The next prime is 1271065125851. The reversal of 1271065125793 is 3975215601721.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 885383138704 + 385681987089 = 940948^2 + 621033^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1271065125793 is a prime.

It is not a weakly prime, because it can be changed into another prime (1271065125703) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 635532562896 + 635532562897.

It is an arithmetic number, because the mean of its divisors is an integer number (635532562897).

Almost surely, 21271065125793 is an apocalyptic number.

It is an amenable number.

1271065125793 is a deficient number, since it is larger than the sum of its proper divisors (1).

1271065125793 is an equidigital number, since it uses as much as digits as its factorization.

1271065125793 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 793800, while the sum is 49.

The spelling of 1271065125793 in words is "one trillion, two hundred seventy-one billion, sixty-five million, one hundred twenty-five thousand, seven hundred ninety-three".