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12735113136 = 243265314857
BaseRepresentation
bin10111101110001001…
…00110011110110000
31012212112100202222220
423313010212132300
5202040142110021
65503405401040
7630405450504
oct136704463660
935775322886
1012735113136
115445703a99
122574b69180
13127c549305
1488b4d6304
154e807bcc6
hex2f71267b0

12735113136 has 20 divisors (see below), whose sum is σ = 32899042392. Its totient is φ = 4245037696.

The previous prime is 12735113107. The next prime is 12735113137. The reversal of 12735113136 is 63131153721.

It is a super-3 number, since 3×127351131363 (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12735113097 and 12735113106.

It is not an unprimeable number, because it can be changed into a prime (12735113137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132657381 + ... + 132657476.

Almost surely, 212735113136 is an apocalyptic number.

12735113136 is a gapful number since it is divisible by the number (16) formed by its first and last digit.

It is an amenable number.

12735113136 is an abundant number, since it is smaller than the sum of its proper divisors (20163929256).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12735113136 is a wasteful number, since it uses less digits than its factorization.

12735113136 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 265314868 (or 265314862 counting only the distinct ones).

The product of its digits is 11340, while the sum is 33.

Adding to 12735113136 its reverse (63131153721), we get a palindrome (75866266857).

The spelling of 12735113136 in words is "twelve billion, seven hundred thirty-five million, one hundred thirteen thousand, one hundred thirty-six".

Divisors: 1 2 3 4 6 8 12 16 24 48 265314857 530629714 795944571 1061259428 1591889142 2122518856 3183778284 4245037712 6367556568 12735113136