Base | Representation |
---|---|
bin | 10010100010011011100… |
… | …011000101010111011001 |
3 | 11111210012200012102111212 |
4 | 102202123203011113121 |
5 | 131332442004010423 |
6 | 2413121502232505 |
7 | 161015632131506 |
oct | 22423343052731 |
9 | 4453180172455 |
10 | 1273919985113 |
11 | 4512a2690a86 |
12 | 186a89285735 |
13 | 9318cbb9979 |
14 | 4592d9c64ad |
15 | 2320e518578 |
hex | 1289b8c55d9 |
1273919985113 has 2 divisors, whose sum is σ = 1273919985114. Its totient is φ = 1273919985112.
The previous prime is 1273919985061. The next prime is 1273919985137. The reversal of 1273919985113 is 3115899193721.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 654097590169 + 619822394944 = 808763^2 + 787288^2 .
It is a cyclic number.
It is not a de Polignac number, because 1273919985113 - 214 = 1273919968729 is a prime.
It is a super-2 number, since 2×12739199851132 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (1273919985913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 636959992556 + 636959992557.
It is an arithmetic number, because the mean of its divisors is an integer number (636959992557).
Almost surely, 21273919985113 is an apocalyptic number.
It is an amenable number.
1273919985113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1273919985113 is an equidigital number, since it uses as much as digits as its factorization.
1273919985113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3674160, while the sum is 59.
The spelling of 1273919985113 in words is "one trillion, two hundred seventy-three billion, nine hundred nineteen million, nine hundred eighty-five thousand, one hundred thirteen".
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