127406433113 has 2 divisors, whose sum is σ = 127406433114. Its totient is φ = 127406433112.

The previous prime is 127406433097. The next prime is 127406433127. The reversal of 127406433113 is 311334604721.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 125151797824 + 2254635289 = 353768^2 + 47483^2 .

It is a cyclic number.

It is not a de Polignac number, because 127406433113 - 2⁴ = 127406433097 is a prime.

It is not a weakly prime, because it can be changed into another prime (127406435113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63703216556 + 63703216557.

It is an arithmetic number, because the mean of its divisors is an integer number (63703216557).

Almost surely, 2^127406433113 is an apocalyptic number.

It is an amenable number.

127406433113 is a deficient number, since it is larger than the sum of its proper divisors (1).

127406433113 is an equidigital number, since it uses as much as digits as its factorization.

127406433113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36288, while the sum is 35.

The spelling of 127406433113 in words is "one hundred twenty-seven billion, four hundred six million, four hundred thirty-three thousand, one hundred thirteen".