12770140253 has 4 divisors (see below), whose sum is σ = 13752458748. Its totient is φ = 11787821760.

The previous prime is 12770140231. The next prime is 12770140267. The reversal of 12770140253 is 35204107721.

12770140253 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 35204107721 = 29 ⋅1213934749.

It can be written as a sum of positive squares in 2 ways, for example, as 1115426404 + 11654713849 = 33398^2 + 107957^2 .

It is not a de Polignac number, because 12770140253 - 2⁸ = 12770139997 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12770140553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 491159228 + ... + 491159253.

It is an arithmetic number, because the mean of its divisors is an integer number (3438114687).

Almost surely, 2^12770140253 is an apocalyptic number.

12770140253 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

12770140253 is a deficient number, since it is larger than the sum of its proper divisors (982318495).

12770140253 is an equidigital number, since it uses as much as digits as its factorization.

12770140253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 982318494.

The product of its (nonzero) digits is 11760, while the sum is 32.

Adding to 12770140253 its reverse (35204107721), we get a palindrome (47974247974).

The spelling of 12770140253 in words is "twelve billion, seven hundred seventy million, one hundred forty thousand, two hundred fifty-three".