Base | Representation |
---|---|
bin | 111011011110001101… |
… | …0110111101101110011 |
3 | 110012122200200222220111 |
4 | 1312330122313231303 |
5 | 4043030043242042 |
6 | 134401020122151 |
7 | 12140621251165 |
oct | 1667432675563 |
9 | 405580628814 |
10 | 127715212147 |
11 | 4a1889a9206 |
12 | 20903696357 |
13 | c074727763 |
14 | 6277c7a935 |
15 | 34c7499517 |
hex | 1dbc6b7b73 |
127715212147 has 2 divisors, whose sum is σ = 127715212148. Its totient is φ = 127715212146.
The previous prime is 127715212139. The next prime is 127715212171. The reversal of 127715212147 is 741212517721.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 127715212147 - 23 = 127715212139 is a prime.
It is a super-2 number, since 2×1277152121472 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (127715213147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63857606073 + 63857606074.
It is an arithmetic number, because the mean of its divisors is an integer number (63857606074).
Almost surely, 2127715212147 is an apocalyptic number.
127715212147 is a deficient number, since it is larger than the sum of its proper divisors (1).
127715212147 is an equidigital number, since it uses as much as digits as its factorization.
127715212147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 54880, while the sum is 40.
Adding to 127715212147 its reverse (741212517721), we get a palindrome (868927729868).
The spelling of 127715212147 in words is "one hundred twenty-seven billion, seven hundred fifteen million, two hundred twelve thousand, one hundred forty-seven".
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