127835100476353 has 2 divisors, whose sum is σ = 127835100476354. Its totient is φ = 127835100476352.

The previous prime is 127835100476309. The next prime is 127835100476387. The reversal of 127835100476353 is 353674001538721.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72065973332224 + 55769127144129 = 8489168^2 + 7467873^2 .

It is a cyclic number.

It is not a de Polignac number, because 127835100476353 - 2³³ = 127826510541761 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 127835100476294 and 127835100476303.

It is not a weakly prime, because it can be changed into another prime (127835700476353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63917550238176 + 63917550238177.

It is an arithmetic number, because the mean of its divisors is an integer number (63917550238177).

Almost surely, 2^{127835100476353} is an apocalyptic number.

It is an amenable number.

127835100476353 is a deficient number, since it is larger than the sum of its proper divisors (1).

127835100476353 is an equidigital number, since it uses as much as digits as its factorization.

127835100476353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12700800, while the sum is 55.

The spelling of 127835100476353 in words is "one hundred twenty-seven trillion, eight hundred thirty-five billion, one hundred million, four hundred seventy-six thousand, three hundred fifty-three".