Base | Representation |
---|---|
bin | 10111110100111001… |
… | …00011110100001001 |
3 | 1020000110212222022111 |
4 | 23322130203310021 |
5 | 202144140202241 |
6 | 5513151022321 |
7 | 631663604554 |
oct | 137234436411 |
9 | 36013788274 |
10 | 12791725321 |
11 | 5474660621 |
12 | 258bb0a9a1 |
13 | 128b1ab24b |
14 | 894c3169b |
15 | 4ed010c81 |
hex | 2fa723d09 |
12791725321 has 2 divisors, whose sum is σ = 12791725322. Its totient is φ = 12791725320.
The previous prime is 12791725307. The next prime is 12791725367. The reversal of 12791725321 is 12352719721.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8021889225 + 4769836096 = 89565^2 + 69064^2 .
It is an emirp because it is prime and its reverse (12352719721) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12791725321 is a prime.
It is not a weakly prime, because it can be changed into another prime (12791725301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6395862660 + 6395862661.
It is an arithmetic number, because the mean of its divisors is an integer number (6395862661).
Almost surely, 212791725321 is an apocalyptic number.
It is an amenable number.
12791725321 is a deficient number, since it is larger than the sum of its proper divisors (1).
12791725321 is an equidigital number, since it uses as much as digits as its factorization.
12791725321 is an evil number, because the sum of its binary digits is even.
The product of its digits is 52920, while the sum is 40.
The spelling of 12791725321 in words is "twelve billion, seven hundred ninety-one million, seven hundred twenty-five thousand, three hundred twenty-one".
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