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128002631400 = 23365272192341
BaseRepresentation
bin111011100110110001…
…1010010011011101000
3110020101201112102000000
41313031203102123220
54044122133201100
6134445324343000
712151011262200
oct1671543223350
9406351472000
10128002631400
114a31616a586
12209839a4a60
13c0bc13c117
1462a40d7400
1534e2820900
hex1dcd8d26e8

128002631400 has 2016 divisors, whose sum is σ = 584034494400. Its totient is φ = 25866086400.

The previous prime is 128002631399. The next prime is 128002631411. The reversal of 128002631400 is 4136200821.

128002631400 is a `hidden beast` number, since 1 + 28 + 0 + 0 + 2 + 631 + 4 + 0 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is an unprimeable number.

It is a polite number, since it can be written in 503 ways as a sum of consecutive naturals, for example, 3122015380 + ... + 3122015420.

It is an arithmetic number, because the mean of its divisors is an integer number (289699650).

Almost surely, 2128002631400 is an apocalyptic number.

128002631400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 128002631400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (292017247200).

128002631400 is an abundant number, since it is smaller than the sum of its proper divisors (456031863000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

128002631400 is a wasteful number, since it uses less digits than its factorization.

128002631400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 131 (or 100 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 27.

The spelling of 128002631400 in words is "one hundred twenty-eight billion, two million, six hundred thirty-one thousand, four hundred".