12801201535417 has 2 divisors, whose sum is σ = 12801201535418. Its totient is φ = 12801201535416.

The previous prime is 12801201535411. The next prime is 12801201535471. The reversal of 12801201535417 is 71453510210821.

12801201535417 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (12801201535471) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12245492414736 + 555709120681 = 3499356^2 + 745459^2 .

It is a cyclic number.

It is not a de Polignac number, because 12801201535417 - 2⁴³ = 4005108513209 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12801201535417.

It is not a weakly prime, because it can be changed into another prime (12801201535411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6400600767708 + 6400600767709.

It is an arithmetic number, because the mean of its divisors is an integer number (6400600767709).

Almost surely, 2^{12801201535417} is an apocalyptic number.

It is an amenable number.

12801201535417 is a deficient number, since it is larger than the sum of its proper divisors (1).

12801201535417 is an equidigital number, since it uses as much as digits as its factorization.

12801201535417 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 67200, while the sum is 40.

The spelling of 12801201535417 in words is "twelve trillion, eight hundred one billion, two hundred one million, five hundred thirty-five thousand, four hundred seventeen".