Base | Representation |
---|---|
bin | 11101000111000101010001… |
… | …000100011101111011110011 |
3 | 121210022112220122012100202010 |
4 | 131013011101010131323303 |
5 | 113240121010301032042 |
6 | 1132144104415454003 |
7 | 35652602515140435 |
oct | 3507052104357363 |
9 | 553275818170663 |
10 | 128030040252147 |
11 | 37881264a93510 |
12 | 124390b5527303 |
13 | 565924783a457 |
14 | 2388989234655 |
15 | ec054d9e659c |
hex | 74715111def3 |
128030040252147 has 32 divisors (see below), whose sum is σ = 186415258371840. Its totient is φ = 77514928168320.
The previous prime is 128030040252131. The next prime is 128030040252161. The reversal of 128030040252147 is 741252040030821.
It is a happy number.
It is not a de Polignac number, because 128030040252147 - 24 = 128030040252131 is a prime.
It is not an unprimeable number, because it can be changed into a prime (128030040252197) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 207402288 + ... + 208018674.
It is an arithmetic number, because the mean of its divisors is an integer number (5825476824120).
Almost surely, 2128030040252147 is an apocalyptic number.
128030040252147 is a deficient number, since it is larger than the sum of its proper divisors (58385218119693).
128030040252147 is a wasteful number, since it uses less digits than its factorization.
128030040252147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 622803.
The product of its (nonzero) digits is 107520, while the sum is 39.
Adding to 128030040252147 its reverse (741252040030821), we get a palindrome (869282080282968).
The spelling of 128030040252147 in words is "one hundred twenty-eight trillion, thirty billion, forty million, two hundred fifty-two thousand, one hundred forty-seven".
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