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128043150145 = 525608630029
BaseRepresentation
bin111011100111111110…
…1110110101101000001
3110020111112202222021021
41313033331312231001
54044213021301040
6134453333025441
712152012550511
oct1671775665501
9406445688237
10128043150145
114a337024949
1220995485281
13c0c7657b01
1462a9643841
1534e617624a
hex1dcff76b41

128043150145 has 4 divisors (see below), whose sum is σ = 153651780180. Its totient is φ = 102434520112.

The previous prime is 128043150127. The next prime is 128043150223. The reversal of 128043150145 is 541051340821.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 14552320689 + 113490829456 = 120633^2 + 336884^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-128043150145 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 128043150145.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12804315010 + ... + 12804315019.

It is an arithmetic number, because the mean of its divisors is an integer number (38412945045).

Almost surely, 2128043150145 is an apocalyptic number.

It is an amenable number.

128043150145 is a deficient number, since it is larger than the sum of its proper divisors (25608630035).

128043150145 is an equidigital number, since it uses as much as digits as its factorization.

128043150145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25608630034.

The product of its (nonzero) digits is 19200, while the sum is 34.

Adding to 128043150145 its reverse (541051340821), we get a palindrome (669094490966).

The spelling of 128043150145 in words is "one hundred twenty-eight billion, forty-three million, one hundred fifty thousand, one hundred forty-five".

Divisors: 1 5 25608630029 128043150145