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128043150127 is a prime number
BaseRepresentation
bin111011100111111110…
…1110110101100101111
3110020111112202222020121
41313033331312230233
54044213021301002
6134453333025411
712152012550454
oct1671775665457
9406445688217
10128043150127
114a337024932
1220995485267
13c0c7657ab9
1462a964382b
1534e6176237
hex1dcff76b2f

128043150127 has 2 divisors, whose sum is σ = 128043150128. Its totient is φ = 128043150126.

The previous prime is 128043150089. The next prime is 128043150223. The reversal of 128043150127 is 721051340821.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-128043150127 is a prime.

It is a super-2 number, since 2×1280431501272 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 128043150092 and 128043150101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (128043150227) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64021575063 + 64021575064.

It is an arithmetic number, because the mean of its divisors is an integer number (64021575064).

Almost surely, 2128043150127 is an apocalyptic number.

128043150127 is a deficient number, since it is larger than the sum of its proper divisors (1).

128043150127 is an equidigital number, since it uses as much as digits as its factorization.

128043150127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13440, while the sum is 34.

Adding to 128043150127 its reverse (721051340821), we get a palindrome (849094490948).

The spelling of 128043150127 in words is "one hundred twenty-eight billion, forty-three million, one hundred fifty thousand, one hundred twenty-seven".