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12806892513543 = 319317247816929
BaseRepresentation
bin1011101001011101011001…
…0001110110100100000111
31200100022211100200210212110
42322113112101312210013
53134312003440413133
643123223304552103
72461160510141142
oct272272621664407
950308740623773
1012806892513543
114098410a48a87
12152a08a482633
1371b8b9609c2b
14323bdd4c1059
1517320b398c63
hexba5d6476907

12806892513543 has 16 divisors (see below), whose sum is σ = 18554411340800. Its totient is φ = 7827642282240.

The previous prime is 12806892513479. The next prime is 12806892513553. The reversal of 12806892513543 is 34531529860821.

It is not a de Polignac number, because 12806892513543 - 26 = 12806892513479 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (57).

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12806892513553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3623906698 + ... + 3623910231.

It is an arithmetic number, because the mean of its divisors is an integer number (1159650708800).

Almost surely, 212806892513543 is an apocalyptic number.

12806892513543 is a deficient number, since it is larger than the sum of its proper divisors (5747518827257).

12806892513543 is a wasteful number, since it uses less digits than its factorization.

12806892513543 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7247816982.

The product of its (nonzero) digits is 12441600, while the sum is 57.

The spelling of 12806892513543 in words is "twelve trillion, eight hundred six billion, eight hundred ninety-two million, five hundred thirteen thousand, five hundred forty-three".

Divisors: 1 3 19 31 57 93 589 1767 7247816929 21743450787 137708521651 224682324799 413125564953 674046974397 4268964171181 12806892513543