Base | Representation |
---|---|
bin | 1011101001011101011001… |
… | …0001110110100100010001 |
3 | 1200100022211100200210212211 |
4 | 2322113112101312210101 |
5 | 3134312003440413203 |
6 | 43123223304552121 |
7 | 2461160510141155 |
oct | 272272621664421 |
9 | 50308740623784 |
10 | 12806892513553 |
11 | 4098410a48a96 |
12 | 152a08a482641 |
13 | 71b8b9609c38 |
14 | 323bdd4c1065 |
15 | 17320b398c6d |
hex | ba5d6476911 |
12806892513553 has 2 divisors, whose sum is σ = 12806892513554. Its totient is φ = 12806892513552.
The previous prime is 12806892513479. The next prime is 12806892513557. The reversal of 12806892513553 is 35531529860821.
12806892513553 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6981099299329 + 5825793214224 = 2642177^2 + 2413668^2 .
It is a cyclic number.
It is not a de Polignac number, because 12806892513553 - 221 = 12806890416401 is a prime.
It is not a weakly prime, because it can be changed into another prime (12806892513557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6403446256776 + 6403446256777.
It is an arithmetic number, because the mean of its divisors is an integer number (6403446256777).
Almost surely, 212806892513553 is an apocalyptic number.
It is an amenable number.
12806892513553 is a deficient number, since it is larger than the sum of its proper divisors (1).
12806892513553 is an equidigital number, since it uses as much as digits as its factorization.
12806892513553 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552000, while the sum is 58.
The spelling of 12806892513553 in words is "twelve trillion, eight hundred six billion, eight hundred ninety-two million, five hundred thirteen thousand, five hundred fifty-three".
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