Base | Representation |
---|---|
bin | 111011101000111110… |
… | …0101101101010111001 |
3 | 110020120212100111221121 |
4 | 1313101330231222321 |
5 | 4044300024433213 |
6 | 134500521505241 |
7 | 12152565324634 |
oct | 1672174555271 |
9 | 406525314847 |
10 | 128076405433 |
11 | 4a353879059 |
12 | 209a4642221 |
13 | c1014cc6b2 |
14 | 62adc1cc1b |
15 | 34e904488d |
hex | 1dd1f2dab9 |
128076405433 has 2 divisors, whose sum is σ = 128076405434. Its totient is φ = 128076405432.
The previous prime is 128076405371. The next prime is 128076405467. The reversal of 128076405433 is 334504670821.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 67054066704 + 61022338729 = 258948^2 + 247027^2 .
It is a cyclic number.
It is not a de Polignac number, because 128076405433 - 29 = 128076404921 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 128076405433.
It is not a weakly prime, because it can be changed into another prime (128076105433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64038202716 + 64038202717.
It is an arithmetic number, because the mean of its divisors is an integer number (64038202717).
Almost surely, 2128076405433 is an apocalyptic number.
It is an amenable number.
128076405433 is a deficient number, since it is larger than the sum of its proper divisors (1).
128076405433 is an equidigital number, since it uses as much as digits as its factorization.
128076405433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 483840, while the sum is 43.
The spelling of 128076405433 in words is "one hundred twenty-eight billion, seventy-six million, four hundred five thousand, four hundred thirty-three".
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