Base | Representation |
---|---|
bin | 10111110111110101… |
… | …01101110100100011 |
3 | 1020002012022222100222 |
4 | 23323322231310203 |
5 | 202222000022333 |
6 | 5515432033255 |
7 | 632413445351 |
oct | 137372556443 |
9 | 36065288328 |
10 | 12816407843 |
11 | 54875899a8 |
12 | 259823282b |
13 | 1293340aa5 |
14 | 8982187d1 |
15 | 500289298 |
hex | 2fbeadd23 |
12816407843 has 2 divisors, whose sum is σ = 12816407844. Its totient is φ = 12816407842.
The previous prime is 12816407803. The next prime is 12816407873. The reversal of 12816407843 is 34870461821.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12816407843 is a prime.
It is a super-2 number, since 2×128164078432 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12816407794 and 12816407803.
It is not a weakly prime, because it can be changed into another prime (12816407803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6408203921 + 6408203922.
It is an arithmetic number, because the mean of its divisors is an integer number (6408203922).
Almost surely, 212816407843 is an apocalyptic number.
12816407843 is a deficient number, since it is larger than the sum of its proper divisors (1).
12816407843 is an equidigital number, since it uses as much as digits as its factorization.
12816407843 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 258048, while the sum is 44.
The spelling of 12816407843 in words is "twelve billion, eight hundred sixteen million, four hundred seven thousand, eight hundred forty-three".
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