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128196799153 is a prime number
BaseRepresentation
bin111011101100100011…
…1111110101010110001
3110020220020220011002021
41313121013332222301
54100021340033103
6134520502151441
712155556546013
oct1673107765261
9406806804067
10128196799153
114a4058296a5
1220a18a22581
13c120433897
1462c1bdc1b3
1535048c6bbd
hex1dd91feab1

128196799153 has 2 divisors, whose sum is σ = 128196799154. Its totient is φ = 128196799152.

The previous prime is 128196799117. The next prime is 128196799219. The reversal of 128196799153 is 351997691821.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106711982224 + 21484816929 = 326668^2 + 146577^2 .

It is an emirp because it is prime and its reverse (351997691821) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 128196799153 - 213 = 128196790961 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 128196799091 and 128196799100.

It is not a weakly prime, because it can be changed into another prime (128196799103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64098399576 + 64098399577.

It is an arithmetic number, because the mean of its divisors is an integer number (64098399577).

Almost surely, 2128196799153 is an apocalyptic number.

It is an amenable number.

128196799153 is a deficient number, since it is larger than the sum of its proper divisors (1).

128196799153 is an equidigital number, since it uses as much as digits as its factorization.

128196799153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7348320, while the sum is 61.

The spelling of 128196799153 in words is "one hundred twenty-eight billion, one hundred ninety-six million, seven hundred ninety-nine thousand, one hundred fifty-three".