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128255682703 = 4113131775329
BaseRepresentation
bin111011101110010100…
…0100110100010001111
3110021001100200202010111
41313130220212202033
54100131423321303
6134530404220451
712160203213121
oct1673450464217
9407040622114
10128255682703
114a435a97795
1220a3469a727
13c12c6ac615
1462c9969211
153509b58b6d
hex1ddca2688f

128255682703 has 16 divisors (see below), whose sum is σ = 132806187360. Its totient is φ = 123778969600.

The previous prime is 128255682689. The next prime is 128255682727. The reversal of 128255682703 is 307286552821.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-128255682703 is a prime.

It is a super-3 number, since 3×1282556827033 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (128255682103) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1664943 + ... + 1740271.

It is an arithmetic number, because the mean of its divisors is an integer number (8300386710).

Almost surely, 2128255682703 is an apocalyptic number.

128255682703 is a deficient number, since it is larger than the sum of its proper divisors (4550504657).

128255682703 is a wasteful number, since it uses less digits than its factorization.

128255682703 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 75818.

The product of its (nonzero) digits is 1612800, while the sum is 49.

The spelling of 128255682703 in words is "one hundred twenty-eight billion, two hundred fifty-five million, six hundred eighty-two thousand, seven hundred three".

Divisors: 1 41 131 317 5371 12997 41527 75329 1702607 3088489 9868099 23879293 404592059 979051013 3128187383 128255682703