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12825730524137 is a prime number
BaseRepresentation
bin1011101010100011100100…
…0111001010001111101001
31200102010110012201220022112
42322220321013022033221
53140114044003233022
643140020444532105
72462425362450626
oct272507107121751
950363405656275
1012825730524137
1140a53a8573183
121531867251035
137205cc33b56b
14324aa932d34d
151739600d68e2
hexbaa391ca3e9

12825730524137 has 2 divisors, whose sum is σ = 12825730524138. Its totient is φ = 12825730524136.

The previous prime is 12825730524043. The next prime is 12825730524143. The reversal of 12825730524137 is 73142503752821.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7377329583376 + 5448400940761 = 2716124^2 + 2334181^2 .

It is an emirp because it is prime and its reverse (73142503752821) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12825730524137 - 214 = 12825730507753 is a prime.

It is not a weakly prime, because it can be changed into another prime (12825730520137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6412865262068 + 6412865262069.

It is an arithmetic number, because the mean of its divisors is an integer number (6412865262069).

Almost surely, 212825730524137 is an apocalyptic number.

It is an amenable number.

12825730524137 is a deficient number, since it is larger than the sum of its proper divisors (1).

12825730524137 is an equidigital number, since it uses as much as digits as its factorization.

12825730524137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2822400, while the sum is 50.

The spelling of 12825730524137 in words is "twelve trillion, eight hundred twenty-five billion, seven hundred thirty million, five hundred twenty-four thousand, one hundred thirty-seven".