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128259012113 is a prime number
BaseRepresentation
bin111011101110011010…
…1010011011000010001
3110021001120221220012222
41313130311103120101
54100133301341423
6134531003430425
712160243420631
oct1673465233021
9407046856188
10128259012113
114a437961171
1220a35825415
13c1302a6b9b
1462ca1946c1
15350a0b53c8
hex1ddcd53611

128259012113 has 2 divisors, whose sum is σ = 128259012114. Its totient is φ = 128259012112.

The previous prime is 128259012083. The next prime is 128259012173. The reversal of 128259012113 is 311210952821.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 102597214864 + 25661797249 = 320308^2 + 160193^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-128259012113 is a prime.

It is not a weakly prime, because it can be changed into another prime (128259012173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64129506056 + 64129506057.

It is an arithmetic number, because the mean of its divisors is an integer number (64129506057).

Almost surely, 2128259012113 is an apocalyptic number.

It is an amenable number.

128259012113 is a deficient number, since it is larger than the sum of its proper divisors (1).

128259012113 is an equidigital number, since it uses as much as digits as its factorization.

128259012113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 35.

Adding to 128259012113 its reverse (311210952821), we get a palindrome (439469964934).

The spelling of 128259012113 in words is "one hundred twenty-eight billion, two hundred fifty-nine million, twelve thousand, one hundred thirteen".