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1282688041 is a prime number
BaseRepresentation
bin100110001110100…
…0100010000101001
310022101121022012111
41030131010100221
510111332004131
6331140242321
743533445165
oct11435042051
93271538174
101282688041
115a9053568
122b96a03a1
1317598620b
14c24d5ca5
1577920ab1
hex4c744429

1282688041 has 2 divisors, whose sum is σ = 1282688042. Its totient is φ = 1282688040.

The previous prime is 1282687963. The next prime is 1282688117. The reversal of 1282688041 is 1408862821.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1148938816 + 133749225 = 33896^2 + 11565^2 .

It is a cyclic number.

It is not a de Polignac number, because 1282688041 - 217 = 1282556969 is a prime.

It is a super-2 number, since 2×12826880412 = 3290577221048835362, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1282687985 and 1282688003.

It is not a weakly prime, because it can be changed into another prime (1282680041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 641344020 + 641344021.

It is an arithmetic number, because the mean of its divisors is an integer number (641344021).

Almost surely, 21282688041 is an apocalyptic number.

It is an amenable number.

1282688041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1282688041 is an equidigital number, since it uses as much as digits as its factorization.

1282688041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 49152, while the sum is 40.

The square root of 1282688041 is about 35814.6344529719. The cubic root of 1282688041 is about 1086.5265637412.

The spelling of 1282688041 in words is "one billion, two hundred eighty-two million, six hundred eighty-eight thousand, forty-one".