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128345281713035 = 529979125153339
BaseRepresentation
bin11101001011101010110110…
…111011001101001110001011
3121211102200121100121211020122
4131023222312323031032023
5113310302114104304120
61132545001454213455
736014432504301122
oct3513526673151613
9554380540554218
10128345281713035
1137992a23632982
121248a2131b428b
13567cba6227b6a
142399d32692ab9
15ec884e2b3a25
hex74bab6ecd38b

128345281713035 has 16 divisors (see below), whose sum is σ = 160967704917600. Its totient is φ = 98113648690176.

The previous prime is 128345281712959. The next prime is 128345281713067. The reversal of 128345281713035 is 530317182543821.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-128345281713035 is a prime.

It is a super-2 number, since 2×1283452817130352 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4562562605 + ... + 4562590734.

It is an arithmetic number, because the mean of its divisors is an integer number (10060481557350).

Almost surely, 2128345281713035 is an apocalyptic number.

128345281713035 is a deficient number, since it is larger than the sum of its proper divisors (32622423204565).

128345281713035 is an equidigital number, since it uses as much as digits as its factorization.

128345281713035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9125153470.

The product of its (nonzero) digits is 4838400, while the sum is 53.

The spelling of 128345281713035 in words is "one hundred twenty-eight trillion, three hundred forty-five billion, two hundred eighty-one million, seven hundred thirteen thousand, thirty-five".

Divisors: 1 5 29 97 145 485 2813 14065 9125153339 45625766695 264629446831 885139873883 1323147234155 4425699369415 25669056342607 128345281713035