Base | Representation |
---|---|
bin | 11101001011101010110110… |
… | …111011001101001110001011 |
3 | 121211102200121100121211020122 |
4 | 131023222312323031032023 |
5 | 113310302114104304120 |
6 | 1132545001454213455 |
7 | 36014432504301122 |
oct | 3513526673151613 |
9 | 554380540554218 |
10 | 128345281713035 |
11 | 37992a23632982 |
12 | 1248a2131b428b |
13 | 567cba6227b6a |
14 | 2399d32692ab9 |
15 | ec884e2b3a25 |
hex | 74bab6ecd38b |
128345281713035 has 16 divisors (see below), whose sum is σ = 160967704917600. Its totient is φ = 98113648690176.
The previous prime is 128345281712959. The next prime is 128345281713067. The reversal of 128345281713035 is 530317182543821.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-128345281713035 is a prime.
It is a super-2 number, since 2×1283452817130352 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4562562605 + ... + 4562590734.
It is an arithmetic number, because the mean of its divisors is an integer number (10060481557350).
Almost surely, 2128345281713035 is an apocalyptic number.
128345281713035 is a deficient number, since it is larger than the sum of its proper divisors (32622423204565).
128345281713035 is an equidigital number, since it uses as much as digits as its factorization.
128345281713035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9125153470.
The product of its (nonzero) digits is 4838400, while the sum is 53.
The spelling of 128345281713035 in words is "one hundred twenty-eight trillion, three hundred forty-five billion, two hundred eighty-one million, seven hundred thirteen thousand, thirty-five".
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