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12836348329697 is a prime number
BaseRepresentation
bin1011101011001011000111…
…1110110111111011100001
31200110010212012000022100022
42322302301332313323201
53140302320133022242
643144534221203225
72463252451351154
oct272626176677341
950403765008308
1012836348329697
1140a9956a976a2
12153392b100515
13721602019c49
143253d5551c9b
15173d8232d0d2
hexbacb1fb7ee1

12836348329697 has 2 divisors, whose sum is σ = 12836348329698. Its totient is φ = 12836348329696.

The previous prime is 12836348329591. The next prime is 12836348329733. The reversal of 12836348329697 is 79692384363821.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12704669338321 + 131678991376 = 3564361^2 + 362876^2 .

It is a cyclic number.

It is not a de Polignac number, because 12836348329697 - 216 = 12836348264161 is a prime.

It is a super-2 number, since 2×128363483296972 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12836348329697.

It is not a weakly prime, because it can be changed into another prime (12836348329997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6418174164848 + 6418174164849.

It is an arithmetic number, because the mean of its divisors is an integer number (6418174164849).

Almost surely, 212836348329697 is an apocalyptic number.

It is an amenable number.

12836348329697 is a deficient number, since it is larger than the sum of its proper divisors (1).

12836348329697 is an equidigital number, since it uses as much as digits as its factorization.

12836348329697 is an evil number, because the sum of its binary digits is even.

The product of its digits is 564350976, while the sum is 71.

The spelling of 12836348329697 in words is "twelve trillion, eight hundred thirty-six billion, three hundred forty-eight million, three hundred twenty-nine thousand, six hundred ninety-seven".