12838161641471 has 4 divisors (see below), whose sum is σ = 12838239139752. Its totient is φ = 12838084143192.

The previous prime is 12838161641363. The next prime is 12838161641527. The reversal of 12838161641471 is 17414616183821.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12838161641471 - 2⁴² = 8440115130367 is a prime.

It is a super-3 number, since 3×12838161641471³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12838161241471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38500121 + ... + 38832146.

It is an arithmetic number, because the mean of its divisors is an integer number (3209559784938).

Almost surely, 2^{12838161641471} is an apocalyptic number.

12838161641471 is a deficient number, since it is larger than the sum of its proper divisors (77498281).

12838161641471 is an equidigital number, since it uses as much as digits as its factorization.

12838161641471 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 77498280.

The product of its digits is 1548288, while the sum is 53.

The spelling of 12838161641471 in words is "twelve trillion, eight hundred thirty-eight billion, one hundred sixty-one million, six hundred forty-one thousand, four hundred seventy-one".