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1284005281121 is a prime number
BaseRepresentation
bin10010101011110100101…
…011011011110101100001
311112202020112110112202122
4102223310223123311201
5132014120322443441
62421510333154025
7161523563545043
oct22536453336541
94482215415678
101284005281121
114555a8564162
12188a2292b915
139410946cc44
14462091cda93
15235eeb2434b
hex12af4adbd61

1284005281121 has 2 divisors, whose sum is σ = 1284005281122. Its totient is φ = 1284005281120.

The previous prime is 1284005281043. The next prime is 1284005281129. The reversal of 1284005281121 is 1211825004821.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 844489319521 + 439515961600 = 918961^2 + 662960^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1284005281121 is a prime.

It is not a weakly prime, because it can be changed into another prime (1284005281129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 642002640560 + 642002640561.

It is an arithmetic number, because the mean of its divisors is an integer number (642002640561).

Almost surely, 21284005281121 is an apocalyptic number.

It is an amenable number.

1284005281121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1284005281121 is an equidigital number, since it uses as much as digits as its factorization.

1284005281121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10240, while the sum is 35.

The spelling of 1284005281121 in words is "one trillion, two hundred eighty-four billion, five million, two hundred eighty-one thousand, one hundred twenty-one".