Search a number
-
+
12840333838 = 26420166919
BaseRepresentation
bin10111111010101011…
…11111001000001110
31020010212100112122221
423331111333020032
5202244111140323
65522044525554
7633124015423
oct137525771016
936125315587
1012840333838
11549a040952
1225a42508ba
13129829a197
1489b485d4a
1550241355d
hex2fd57f20e

12840333838 has 4 divisors (see below), whose sum is σ = 19260500760. Its totient is φ = 6420166918.

The previous prime is 12840333833. The next prime is 12840333839. The reversal of 12840333838 is 83833304821.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 12840333794 and 12840333803.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12840333833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3210083458 + ... + 3210083461.

It is an arithmetic number, because the mean of its divisors is an integer number (4815125190).

Almost surely, 212840333838 is an apocalyptic number.

12840333838 is a deficient number, since it is larger than the sum of its proper divisors (6420166922).

12840333838 is an equidigital number, since it uses as much as digits as its factorization.

12840333838 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6420166921.

The product of its (nonzero) digits is 331776, while the sum is 43.

The spelling of 12840333838 in words is "twelve billion, eight hundred forty million, three hundred thirty-three thousand, eight hundred thirty-eight".

Divisors: 1 2 6420166919 12840333838