Base | Representation |
---|---|
bin | 10111111011000010… |
… | …11111000010111111 |
3 | 1020011002000200112110 |
4 | 23331201133002333 |
5 | 202300344120114 |
6 | 5522233305103 |
7 | 633161441505 |
oct | 137541370277 |
9 | 36132020473 |
10 | 12843348159 |
11 | 54a080a624 |
12 | 25a5265193 |
13 | 1298ab41c5 |
14 | 89ba2c675 |
15 | 50280b759 |
hex | 2fd85f0bf |
12843348159 has 4 divisors (see below), whose sum is σ = 17124464216. Its totient is φ = 8562232104.
The previous prime is 12843348157. The next prime is 12843348181. The reversal of 12843348159 is 95184334821.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 95184334821 = 3 ⋅31728111607.
It is not a de Polignac number, because 12843348159 - 21 = 12843348157 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12843348157) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2140558024 + ... + 2140558029.
It is an arithmetic number, because the mean of its divisors is an integer number (4281116054).
Almost surely, 212843348159 is an apocalyptic number.
12843348159 is a deficient number, since it is larger than the sum of its proper divisors (4281116057).
12843348159 is an equidigital number, since it uses as much as digits as its factorization.
12843348159 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4281116056.
The product of its digits is 829440, while the sum is 48.
The spelling of 12843348159 in words is "twelve billion, eight hundred forty-three million, three hundred forty-eight thousand, one hundred fifty-nine".
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