Base | Representation |
---|---|
bin | 10111111011000010… |
… | …11111000011010101 |
3 | 1020011002000200120021 |
4 | 23331201133003111 |
5 | 202300344120211 |
6 | 5522233305141 |
7 | 633161441536 |
oct | 137541370325 |
9 | 36132020507 |
10 | 12843348181 |
11 | 54a080a644 |
12 | 25a52651b1 |
13 | 1298ab4211 |
14 | 89ba2c68d |
15 | 50280b771 |
hex | 2fd85f0d5 |
12843348181 has 2 divisors, whose sum is σ = 12843348182. Its totient is φ = 12843348180.
The previous prime is 12843348157. The next prime is 12843348197. The reversal of 12843348181 is 18184334821.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12700163025 + 143185156 = 112695^2 + 11966^2 .
It is a cyclic number.
It is not a de Polignac number, because 12843348181 - 25 = 12843348149 is a prime.
It is a super-2 number, since 2×128433481812 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12843348481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6421674090 + 6421674091.
It is an arithmetic number, because the mean of its divisors is an integer number (6421674091).
Almost surely, 212843348181 is an apocalyptic number.
It is an amenable number.
12843348181 is a deficient number, since it is larger than the sum of its proper divisors (1).
12843348181 is an equidigital number, since it uses as much as digits as its factorization.
12843348181 is an evil number, because the sum of its binary digits is even.
The product of its digits is 147456, while the sum is 43.
The spelling of 12843348181 in words is "twelve billion, eight hundred forty-three million, three hundred forty-eight thousand, one hundred eighty-one".
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