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12846714612481 is a prime number
BaseRepresentation
bin1011101011110001101111…
…0111000110101100000001
31200111010121122000000222201
42322330123313012230001
53140440032420044411
643153411010433201
72464100364325021
oct272743367065401
950433548000881
1012846714612481
114103296538352
121535942892801
13722594871a99
14325ada1bda81
1517428c43e3c1
hexbaf1bdc6b01

12846714612481 has 2 divisors, whose sum is σ = 12846714612482. Its totient is φ = 12846714612480.

The previous prime is 12846714612343. The next prime is 12846714612491. The reversal of 12846714612481 is 18421641764821.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10268442122481 + 2578272490000 = 3204441^2 + 1605700^2 .

It is a cyclic number.

It is not a de Polignac number, because 12846714612481 - 217 = 12846714481409 is a prime.

It is a super-2 number, since 2×128467146124812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12846714612491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6423357306240 + 6423357306241.

It is an arithmetic number, because the mean of its divisors is an integer number (6423357306241).

Almost surely, 212846714612481 is an apocalyptic number.

It is an amenable number.

12846714612481 is a deficient number, since it is larger than the sum of its proper divisors (1).

12846714612481 is an equidigital number, since it uses as much as digits as its factorization.

12846714612481 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4128768, while the sum is 55.

The spelling of 12846714612481 in words is "twelve trillion, eight hundred forty-six billion, seven hundred fourteen million, six hundred twelve thousand, four hundred eighty-one".