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12847542303307 is a prime number
BaseRepresentation
bin1011101011110100110100…
…1100011111101001001011
31200111012202022110002100111
42322331031030133221023
53140443231312201212
643154025055015151
72464130034511555
oct272751514375113
950435668402314
1012847542303307
114103680771758
121535b33b0a4b7
1372269719b87a
14325b780b64d5
151742d9e35ea7
hexbaf4d31fa4b

12847542303307 has 2 divisors, whose sum is σ = 12847542303308. Its totient is φ = 12847542303306.

The previous prime is 12847542303289. The next prime is 12847542303403. The reversal of 12847542303307 is 70330324574821.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12847542303307 is a prime.

It is a super-3 number, since 3×128475423033073 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (12847542303107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6423771151653 + 6423771151654.

It is an arithmetic number, because the mean of its divisors is an integer number (6423771151654).

Almost surely, 212847542303307 is an apocalyptic number.

12847542303307 is a deficient number, since it is larger than the sum of its proper divisors (1).

12847542303307 is an equidigital number, since it uses as much as digits as its factorization.

12847542303307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3386880, while the sum is 49.

The spelling of 12847542303307 in words is "twelve trillion, eight hundred forty-seven billion, five hundred forty-two million, three hundred three thousand, three hundred seven".