Base | Representation |
---|---|
bin | 10010101100110000010… |
… | …101111100011011010111 |
3 | 11112211211022000120122021 |
4 | 102230300111330123113 |
5 | 132023143101433112 |
6 | 2422153532114011 |
7 | 161560440110233 |
oct | 22546025743327 |
9 | 4484738016567 |
10 | 1285006280407 |
11 | 455a715aa7a3 |
12 | 189062005907 |
13 | 94238969c05 |
14 | 462a211b5c3 |
15 | 2365c951907 |
hex | 12b3057c6d7 |
1285006280407 has 16 divisors (see below), whose sum is σ = 1344823240960. Its totient is φ = 1226342073600.
The previous prime is 1285006280399. The next prime is 1285006280423. The reversal of 1285006280407 is 7040826005821.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 1285006280407 - 23 = 1285006280399 is a prime.
It is a super-2 number, since 2×12850062804072 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1285006280707) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17209069 + ... + 17283577.
It is an arithmetic number, because the mean of its divisors is an integer number (84051452560).
Almost surely, 21285006280407 is an apocalyptic number.
1285006280407 is a deficient number, since it is larger than the sum of its proper divisors (59816960553).
1285006280407 is an equidigital number, since it uses as much as digits as its factorization.
1285006280407 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82234.
The product of its (nonzero) digits is 215040, while the sum is 43.
The spelling of 1285006280407 in words is "one trillion, two hundred eighty-five billion, six million, two hundred eighty thousand, four hundred seven".
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